Length of slug in drill pipe:
pressure gradient, psi/ft
Volume of slug, barrels:
Example: Determine the barrels of slug required for the following:
Desired length of dry pipe (2 stands) = 184 ft Mud weight = 12.2 ppg
Slug weight = 13.2ppg
Drill pipe capacity = 0.01422 bbl/ft
Hydrostatic pressure required: HP, psi = 12.2 ppg x 0.052 x 184 ft HP = 117 psi
Difference in pressure gradient, psi/ft:
psi/ft = (13.2 ppg - 12.2 ppg) x 0.052 psi/ft = 0.052
Length of slug in drill pipe, ft:
Slug length, ft = 117 psi + 0.052 Slug length = 2250 ft
Volume of slug, bbl: Slug vol, bbl = 2250ft x 0.01422bbl/ft Slug vol = 32.0 bbl
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