Barrels of slug required for a desired length of dry pipe Step

Hydrostatic pressure required to give desired drop inside drill pipe: HP, psi = mud wt, ppg x 0.052 x ft of dry pipe

Step 2

Difference in pressure gradient between slug weight and mud weight: psi/ft = (slug wt, ppg - mud wt, ppg) x 0.052

Step 3

Length of slug in drill pipe:

pressure gradient, psi/ft

Step 4

Volume of slug, barrels:

capacity, bbl/ft

Example: Determine the barrels of slug required for the following:

Desired length of dry pipe (2 stands) = 184 ft Mud weight = 12.2 ppg

Slug weight = 13.2ppg

Drill pipe capacity = 0.01422 bbl/ft

Step 1

Hydrostatic pressure required: HP, psi = 12.2 ppg x 0.052 x 184 ft HP = 117 psi

Step 2

Difference in pressure gradient, psi/ft:

psi/ft = (13.2 ppg - 12.2 ppg) x 0.052 psi/ft = 0.052

Step 3

Length of slug in drill pipe, ft:

Slug length, ft = 117 psi + 0.052 Slug length = 2250 ft

Step 4

Volume of slug, bbl: Slug vol, bbl = 2250ft x 0.01422bbl/ft Slug vol = 32.0 bbl

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